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Python problem 2 of 30

FizzBuzz, as a list

  • Python
  • Easy

Write fizzbuzz(n) that returns a list of strings for the numbers 1 to n. Multiples of 3 become "Fizz", multiples of 5 become "Buzz", multiples of both become "FizzBuzz", and everything else is the number as a string.

fizzbuzz(5)
# ["1", "2", "Fizz", "4", "Buzz"]
Show hint

Build the word by adding "Fizz" and "Buzz" separately. If the word is still empty, use the number.

Show solution 
def fizzbuzz(n):
    out = []
    for i in range(1, n + 1):
        word = ""
        if i % 3 == 0:
            word += "Fizz"
        if i % 5 == 0:
            word += "Buzz"
        out.append(word or str(i))
    return out

Building the word up avoids a separate check for 15, and word or str(i) falls back to the number when the word is empty. This version is easy to extend: adding "Bazz" for 7 is one more if.

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